Copying Dictionaries in Python Without Changing the Original

You will learn that dict2 = dict1 does not copy a dictionary: it gives two variable names access to the same dictionary object. You will also learn when to use a shallow copy such as .copy() and when nested data requires copy.deepcopy().

In Python, a variable does not contain a dictionary itself. Instead, it refers to an object stored elsewhere in memory.

When you write:

dict2 = dict1

Python does not create a second dictionary. It makes dict2 refer to the exact same dictionary as dict1. Therefore, changing the dictionary through either name changes the shared object.

dict1 = {"status": "pending"}
dict2 = dict1

dict2["status"] = "done"

print(dict1["status"])  # done

To edit a separate top-level dictionary, create a shallow copy:

dict2 = dict1.copy()

A shallow copy creates a new outer dictionary, but values inside it may still be shared when those values are mutable objects such as lists or other dictionaries. For completely independent nested data, use copy.deepcopy().

Think of a dictionary as a filing cabinet and a variable as a label pointing to that cabinet.

• dict2 = dict1 puts a second label on the same filing cabinet. Editing files through either label changes the same cabinet.
• dict2 = dict1.copy() creates a new cabinet and copies the top-level files into it.
• deepcopy() creates a new cabinet and also creates new copies of cabinets, folders, and lists stored inside it.

Two variable names do not necessarily mean two separate objects.

Use one of these approaches depending on the dictionary's contents.

Assignment: no copy

dict2 = dict1

Both variables reference one dictionary. This is useful when you intentionally want a shared object.

Shallow copy: new outer dictionary

dict1 = {"key1": "value1", "key2": "value2"}
dict2 = dict1.copy()

dict2["key2"] = "updated value"

print(dict1)  # {'key1': 'value1', 'key2': 'value2'}
print(dict2)  # {'key1': 'value1', 'key2': 'updated value'}

Other shallow-copy syntax:

dict2 = dict(dict1)
dict2 = {**dict1}
dict2 = dict1 | {}  # Python 3.9+

For most code, dict1.copy() is the clearest option.

Deep copy: independent nested objects

from copy import deepcopy

user = {
    "name": "Ava",
    "settings": {"theme": "light"}
}

user_copy = deepcopy(user)
user_copy[][] = 

(user[][])       
(user_copy[][])  

Consider the original assignment:

dict1 = {"key1": "value1", "key2": "value2"}
dict2 = dict1
dict2["key2"] = "WHY?!"

1. Python creates one dictionary object and dict1 refers to it.
2. dict2 = dict1 reads the reference stored in dict1 and stores that same reference in dict2.
3. There is still only one dictionary object.
4. dict2["key2"] = "WHY?!" changes the value in that shared dictionary.
5. Looking up dict1 shows the changed value because dict1 refers to the same object.

You can verify shared identity with is:

print(dict1 is dict2)  # True

Now use a shallow copy:

dict1 = {"key1": "value1", "key2": "value2"}
dict2 = dict1.copy()
dict2[] = 

(dict1  dict2)  
(dict1)           
(dict2)           

Dictionary copies are useful whenever code needs to derive changed data while preserving an original value.

• API request options: Copy default headers or options, then add a request-specific value.
• Application configuration: Start from default settings and create user-specific settings without changing defaults.
• Data transformation: Keep the original record while producing a cleaned or enriched version.
• State updates: Create a new state dictionary before changing fields, making updates easier to reason about.
• Test data: Copy fixture data before each test so one test does not mutate data used by another test.

Example: build request headers without changing shared defaults.

default_headers = {
    "Accept": "application/json",
    "User-Agent": "MyApp/1.0"
}

headers = default_headers.copy()
headers["Authorization"] = "Bearer token-value"

print(default_headers)
# {'Accept': 'application/json', 'User-Agent': 'MyApp/1.0'}

Developers often copy dictionaries at boundaries where data must not be unexpectedly mutated.

Apply defaults safely

def create_settings(overrides):
    defaults = {"theme": "light", "notifications": True}
    settings = defaults.copy()
    settings.update(overrides)
    return settings

This avoids modifying defaults when callers provide overrides.

Return derived data without mutating input

def mark_complete(task):
    updated_task = task.copy()
    updated_task["completed"] = True
    return updated_task

The caller can keep both the original task and the updated task.

Copy nested configuration when it will be edited

from copy import deepcopy

def enable_debug(config):
    updated_config = deepcopy(config)
    updated_config["logging"]["level"] = "DEBUG"
    return updated_config

Assuming assignment creates a copy

This code shares one dictionary:

original = {"role": "viewer"}
copy = original
copy["role"] = "admin"

print(original["role"])  # admin

Use original.copy() when you need a separate outer dictionary.

Forgetting that .copy() is shallow

original = {"tags": ["python", "api"]}
copy = original.copy()

copy["tags"].append("testing")
print(original["tags"])
# ['python', 'api', 'testing']

The outer dictionaries differ, but both contain a reference to the same list. Use deepcopy() or copy the nested list:

copy = original.copy()
copy["tags"] = original["tags"].copy()

Using is to compare dictionary contents

is checks whether two variables refer to the same object. It does not compare values.

# No copy: both names point to one object
alias = original

# Recommended shallow copy
copy = original.copy()

# Other shallow copies
copy = dict(original)
copy = {**original}
copy = original | {}  # Python 3.9+

# Copy and override top-level values
updated = {**original, "status": "done"}

# Deep copy nested mutable values
from copy import deepcopy
copy = deepcopy(original)

# Identity versus content
first is second  # Same object?
first == second  # Same key/value contents?

• Use .copy() for a flat dictionary or when only top-level keys will change.
• A shallow copy still shares nested mutable objects.
• Use deepcopy() when nested dictionaries, lists, or sets must also be independent.
• Assignment (=) creates an alias, not a dictionary copy.

Does dict2 = dict1 copy a dictionary in Python?

No. It creates another reference to the same dictionary object.

What is the simplest way to copy a Python dictionary?

Use dict2 = dict1.copy(). It creates a shallow copy.

Why does changing a nested list affect the original after .copy()?

.copy() only copies the outer dictionary. The nested list is still the same shared list object in both dictionaries.

When should I use copy.deepcopy()?

Use it when you need to modify nested mutable values, such as dictionaries or lists inside a dictionary, without affecting the original.

Is {**dict1} a dictionary copy?

Yes. It creates a new outer dictionary, so it is a shallow copy like dict1.copy().

Does copying a dictionary duplicate strings and integers?

A shallow copy creates a new dictionary container but reuses its values. This is generally safe for immutable values such as strings, integers, and tuples containing only immutable values.

How can I check whether two variables share the same dictionary?

Use is:

print(dict1  dict2)

• Python variables and object references — explains why assignment can share an object rather than duplicate it.
• Mutable vs immutable objects — helps predict whether a change can affect shared values.
• Lists in Python — lists have the same aliasing and shallow-copy behavior.
• Shallow copy vs deep copy — covers nested mutable objects in more detail.
• Dictionary methods — includes .copy(), .update(), .get(), and related operations.
• Equality vs identity (== and is) — distinguishes matching contents from being the same object.